PHP生成嵌套JSON

({

"aa": [

{

"Id": "0",

"title": "标题",

},

{

"Id": "1",

"title": "标题",

}

],

"bb":[

{

...

},

{

....

}

]

})

PHP如何生成这种嵌套的JSON

------解决方案--------------------

/** Json数据格式化

* @param Mixed $data 数据

* @param String $indent 缩进字符，默认4个空格

* @return JSON

*/

function jsonFormat($data, $indent=null){

// 对数组中每个元素递归进行urlencode操作，保护中文字符

array_walk_recursive($data, 'jsonFormatProtect');

// json encode

$data = json_encode($data);

// 将urlencode的内容进行urldecode

$data = urldecode($data);

// 缩进处理

$ret = '';

$pos = 0;

$length = strlen($data);

$indent = isset($indent)? $indent : ' ';

$newline = "n";

$prevchar = '';

$outofquotes = true;

for($i=0; $i<=$length; $i++){

$char = substr($data, $i, 1);

if($char=='"' && $prevchar!=''){

$outofquotes = !$outofquotes;

}elseif(($char=='}' ------解决方案-------------------- $char==']') && $outofquotes){

$ret .= $newline;

$pos --;

for($j=0; $j<$pos; $j++){

$ret .= $indent;

}

}

$ret .= $char;

if(($char==',' ------解决方案-------------------- $char=='{' ------解决方案-------------------- $char=='[') && $outofquotes){

$ret .= $newline;

if($char=='{' ------解决方案-------------------- $char=='['){

$pos ++;

}

for($j=0; $j<$pos; $j++){

$ret .= $indent;

}

}

$prevchar = $char;

}

return $ret;

}

/** 将数组元素进行urlencode

* @param String $val

*/

function jsonFormatProtect(&$val){

if($val!==true && $val!==false && $val!==null){

$val = urlencode($val);

}

}

header('content-type:application/json;charset=utf8');

$arr = array(

'aa' => array(

array(

'Id' => 0,

'title' => '标题'

), array( 'Id' => 1, 'title' => '标题' ), ), 'bb' => array( array( 'Id' => 2, 'title' => '标题' ), array( 'Id' => 3, 'title' => '标题' ), ));echo jsonFormat($arr);{ "aa":[ { "Id":"0", "title":"标题" }, { "Id":"1", "title":"标题" } ], "bb":[ { "Id":"2", "title":"标题" }, { "Id":"3", "title":"标题" } ]}

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