Oracle中检查外键是否有索引的SQL脚本分享
来源: 阅读:715 次 日期:2014-12-30 15:59:50
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代码如下:

COLUMN COLUMNS format a30 word_wrapped

COLUMN tablename format a15 word_wrapped

COLUMN constraint_name format a15 word_wrapped

SELECT TABLE_NAME,

CONSTRAINT_NAME,

CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||

NVL2(CNAME3, ',' || CNAME3, NULL) ||

NVL2(CNAME4, ',' || CNAME4, NULL) ||

NVL2(CNAME5, ',' || CNAME5, NULL) ||

NVL2(CNAME6, ',' || CNAME6, NULL) ||

NVL2(CNAME7, ',' || CNAME7, NULL) ||

NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS

FROM (SELECT B.TABLE_NAME,

B.CONSTRAINT_NAME,

MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,

MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,

MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,

MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,

MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,

MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,

MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,

MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,

COUNT(*) COL_CNT

FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,

SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,

SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,

POSITION

FROM USER_CONS_COLUMNS) A,

USER_CONSTRAINTS B

WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME

AND B.CONSTRAINT_TYPE = 'R'

GROUP BY B.TABLE_NAME, B.CONSTRAINT_NAME) CONS

WHERE COL_CNT > ALL

(SELECT COUNT(*)

FROM USER_IND_COLUMNS I

WHERE I.TABLE_NAME = CONS.TABLE_NAME

AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,

CNAME6, CNAME7, CNAME8)

AND I.COLUMN_POSITION <= CONS.COL_CNT

GROUP BY I.INDEX_NAME)

/

在上面的基础上修改了一下,可以检查所有的用户。

代码如下:

SET linesize 400;

COLUMN OWNER format a10 word_wrapped

COLUMN COLUMNS format a30 word_wrapped

COLUMN TABLE_NAME format a15 word_wrapped

COLUMN CONSTRAINT_NAME format a40 word_wrapped

SELECT OWNER,

TABLE_NAME,

CONSTRAINT_NAME,

CNAME1 || NVL2(CNAME2, ',' || CNAME2, NULL) ||

NVL2(CNAME3, ',' || CNAME3, NULL) ||

NVL2(CNAME4, ',' || CNAME4, NULL) ||

NVL2(CNAME5, ',' || CNAME5, NULL) ||

NVL2(CNAME6, ',' || CNAME6, NULL) ||

NVL2(CNAME7, ',' || CNAME7, NULL) ||

NVL2(CNAME8, ',' || CNAME8, NULL) COLUMNS

FROM (SELECT B.OWNER,B.TABLE_NAME,

B.CONSTRAINT_NAME,

MAX(DECODE(POSITION, 1, COLUMN_NAME, NULL)) CNAME1,

MAX(DECODE(POSITION, 2, COLUMN_NAME, NULL)) CNAME2,

MAX(DECODE(POSITION, 3, COLUMN_NAME, NULL)) CNAME3,

MAX(DECODE(POSITION, 4, COLUMN_NAME, NULL)) CNAME4,

MAX(DECODE(POSITION, 5, COLUMN_NAME, NULL)) CNAME5,

MAX(DECODE(POSITION, 6, COLUMN_NAME, NULL)) CNAME6,

MAX(DECODE(POSITION, 7, COLUMN_NAME, NULL)) CNAME7,

MAX(DECODE(POSITION, 8, COLUMN_NAME, NULL)) CNAME8,

COUNT(*) COL_CNT

FROM (SELECT SUBSTR(TABLE_NAME, 1, 30) TABLE_NAME,

SUBSTR(CONSTRAINT_NAME, 1, 30) CONSTRAINT_NAME,

SUBSTR(COLUMN_NAME, 1, 30) COLUMN_NAME,

POSITION

FROM DBA_CONS_COLUMNS WHERE OWNER NOT IN ('SYS','SYSTEM','SYSMAN','HR','OE','EXFSYS','DBSNMP','MDSYS','OLAPSYS','SCOTT','EXFSYS','SH','PM','CTXSYS')) A,

DBA_CONSTRAINTS B

WHERE A.CONSTRAINT_NAME = B.CONSTRAINT_NAME

AND B.CONSTRAINT_TYPE = 'R'

GROUP BY B.OWNER,B.TABLE_NAME, B.CONSTRAINT_NAME) CONS

WHERE COL_CNT > ALL

(SELECT COUNT(*)

FROM DBA_IND_COLUMNS I

WHERE I.TABLE_NAME = CONS.TABLE_NAME AND I.TABLE_OWNER=CONS.OWNER

AND I.COLUMN_NAME IN (CNAME1, CNAME2, CNAME3, CNAME4, CNAME5,

CNAME6, CNAME7, CNAME8)

AND I.COLUMN_POSITION <= CONS.COL_CNT

GROUP BY I.INDEX_NAME)

/

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