这篇文章主要介绍了PHP日期函数date格式化UNIX时间的方法,实例分析了php中date函数的使用技巧,需要的朋友可以参考下

本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下：

日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出

使用到函数语法如下

string date (string $Format);

string date (string $Format, int $Time);

下面是演示代码

<?php

echo "When this page was loaded,\n";

echo 'It was then ', date ('r'), "\n";

echo 'The currend date was ', date ('F j, Y'), "\n";

echo 'The currend date was ', date ('M j, Y'), "\n";

echo 'The currend date was ', date ('m/d/y'), "\n";

echo 'The currend date was the ', date ('jS \o\f M, Y'), "\n";

echo 'The currend time was ', date ('g:i:s A T'), "\n";

echo 'The currend time was ', date ('H:i:s O'), "\n";

echo date ('Y');

date ('L')?(print ' is'):(print ' is not');

echo " a leap year\n";

echo time ('U'), " seconds had elapsed since January 1, 1970.\n";

?>

输出结果如下

It was then Sat, 26 Dec 2009 07:09:51 +0000

The currend date was December 26, 2009

The currend date was Dec 26, 2009

The currend date was 12/26/09

The currend date was the 26th of Dec, 2009

The currend time was 7:09:51 AM GMT

The currend time was 07:09:51 +0000

2009 is not a leap year

1261811391 seconds had elapsed since January 1, 1970.

希望本文所述对大家的php程序设计有所帮助。

更多信息请查看IT技术专栏